Redox Reaction Balancer

Balance oxidation-reduction equations using the half-reaction method. Supports acidic and basic solutions.

Balance Redox Equation

Enter the unbalanced redox equation and select the medium.

Use + for plus, → or = for arrow. Charges: Fe2+ or Fe^2+
Example Reactions:
⭐ Easy - Acidic Medium
MnO₄⁻ + Fe²⁺ → Mn²⁺ + Fe³⁺ Cr₂O₇²⁻ + Fe²⁺ → Cr³⁺ + Fe³⁺ MnO₄⁻ + Cl⁻ → Mn²⁺ + Cl₂ Cu + NO₃⁻ → Cu²⁺ + NO
⭐⭐ Medium - Basic Medium
MnO₄⁻ + I⁻ → MnO₂ + I₂ Cr(OH)₃ + ClO⁻ → CrO₄²⁻ + Cl⁻ Al + NO₃⁻ → AlO₂⁻ + NH₃ Zn + NO₃⁻ → Zn(OH)₄²⁻ + NH₃
⭐⭐⭐ Hard - Complex Reactions
Cr₂O₇²⁻ + C₂H₅OH → Cr³⁺ + CO₂ (organic) MnO₄⁻ + H₂O₂ → Mn²⁺ + O₂ IO₃⁻ + I⁻ → I₂ (disproportionation) S₂O₃²⁻ + I₂ → S₄O₆²⁻ + I⁻
⭐⭐⭐⭐ Very Hard - Industrial
Dichromate titration (full) Permanganate with oxalic acid As₂S₃ oxidation
Calculate Oxidation Numbers

Determine oxidation numbers for all atoms in a compound or ion.

For ions, include charge: MnO4- or MnO4^-
Example Compounds:
⭐ Simple Compounds
H₂O H₂SO₄ NH₃ CO₂ NaCl
⭐⭐ Polyatomic Ions
MnO₄⁻ Cr₂O₇²⁻ SO₄²⁻ NO₃⁻ PO₄³⁻
⭐⭐⭐ Complex Compounds
K₂Cr₂O₇ KMnO₄ H₂O₂ (peroxide) Fe₃O₄ (mixed) Na₂S₂O₃
Split into Half-Reactions

Separate a redox equation into oxidation and reduction half-reactions.

Enter a balanced redox equation
Example Equations:
⭐ Simple Redox
Fe²⁺/MnO₄⁻ (acidic) Fe²⁺/Cr₂O₇²⁻ Cu/NO₃⁻
⭐⭐ Basic Solutions
MnO₄⁻/I⁻ (basic) Al/NO₃⁻ (basic)
Results


Enter equation and click Balance to see results

Understanding Redox Reactions
Redox Basics

Redox reactions involve the transfer of electrons between species.

  • Oxidation: Loss of electrons (increase in oxidation number)
  • Reduction: Gain of electrons (decrease in oxidation number)
  • Oxidizing Agent: Species that gets reduced
  • Reducing Agent: Species that gets oxidized
Oxidation Number Rules
  1. Free elements: 0
  2. Monatomic ions: charge of ion
  3. Oxygen: usually -2 (except peroxides: -1)
  4. Hydrogen: +1 (with nonmetals), -1 (with metals)
  5. Group 1: +1, Group 2: +2
  6. Sum = total charge
Half-Reaction Method

For Acidic Solutions:

  1. Split into half-reactions
  2. Balance atoms except O and H
  3. Balance O by adding H₂O
  4. Balance H by adding H⁺
  5. Balance charge by adding e⁻
  6. Equalize electrons transferred
  7. Add half-reactions and simplify

For Basic Solutions:

  • Follow acidic method first
  • Add OH⁻ to neutralize H⁺
  • Combine H⁺ + OH⁻ → H₂O
  • Cancel excess H₂O

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