Limiting Reagent Calculator

Calculate the limiting reactant, excess reagent, theoretical yield, and percent yield for chemical reactions.

Limiting Reagent Calculator

Enter a balanced equation with coefficients. Supports: β†’, β‡Œ, =, ==
πŸ’‘ How it works: Enter your equation above and press Tab/Enter. Input fields will be generated automatically with molar masses calculated!
Easy - Synthesis & Decomposition
πŸ’§ Water synthesis πŸ§‚ Sodium chloride Magnesium oxide Hydrogen chloride Potassium chlorate decomp Limestone decomp
Medium - Combustion & Single Replacement
πŸ”₯ Methane combustion Propane combustion Octane combustion Ethanol combustion Zinc + acid Iron + copper sulfate Magnesium + silver nitrate
Hard - Double Replacement & Complex
Precipitation (AgCl) Barium sulfate ppt Lead iodide ppt Neutralization Acid-base titration Phosphoric acid + calcium
Very Hard - Industrial & Redox
βš—οΈ Haber Process Ostwald Process Contact Process Pyrite roasting πŸ”₯ Thermite reaction Iron ore reduction Rust formation Glucose combustion
Organic Chemistry
Ethanol synthesis Bromination of ethene Esterification Benzene hydrogenation Butane combustion
Expert - Multiple Products
Aspirin synthesis Copper + nitric acid Permanganate titration Permanganate + HCl

Calculate with Actual & Percent Yield

Note: First calculate theoretical yield, then enter actual yield to find percent yield.
Understanding Limiting Reagents
What is a Limiting Reagent?

The limiting reagent (or limiting reactant) is the reactant that is completely consumed first in a chemical reaction. It determines the maximum amount of product that can be formed.

Key Concept:
The reactant that produces the LEAST amount of product is the limiting reagent.
Step-by-Step Process
Step 1: Write the balanced chemical equation
Example: 2Hβ‚‚ + Oβ‚‚ β†’ 2Hβ‚‚O
Step 2: Convert all given amounts to moles
β€’ If given grams: moles = grams Γ· molar mass
β€’ If given moles: use directly
Step 3: Calculate mole ratio for each reactant
β€’ Divide moles available by coefficient in balanced equation
β€’ The reactant with the SMALLEST ratio is the limiting reagent
Step 4: Calculate theoretical yield
β€’ Use moles of limiting reagent
β€’ Apply stoichiometry from balanced equation
β€’ Convert to desired unit (g, mol, etc.)
Step 5: Calculate excess reagent remaining
β€’ Determine how much was used based on limiting reagent
β€’ Subtract from initial amount
Example Problem
Problem: 4.0 g of Hβ‚‚ reacts with 32.0 g of Oβ‚‚. Find the limiting reagent and theoretical yield of Hβ‚‚O.

Balanced equation: 2Hβ‚‚ + Oβ‚‚ β†’ 2Hβ‚‚O

Step 1 - Convert to moles:
β€’ Hβ‚‚: 4.0 g Γ· 2.016 g/mol = 1.98 mol
β€’ Oβ‚‚: 32.0 g Γ· 32.00 g/mol = 1.00 mol

Step 2 - Calculate mole ratios:
β€’ Hβ‚‚: 1.98 mol Γ· 2 = 0.99
β€’ Oβ‚‚: 1.00 mol Γ· 1 = 1.00

Result: Hβ‚‚ is the limiting reagent (smallest ratio)

Step 3 - Theoretical yield:
β€’ From equation: 2 mol Hβ‚‚ β†’ 2 mol Hβ‚‚O
β€’ So: 1.98 mol Hβ‚‚ β†’ 1.98 mol Hβ‚‚O
β€’ Mass: 1.98 mol Γ— 18.015 g/mol = 35.7 g Hβ‚‚O
Percent Yield

Percent yield compares actual yield (what you got in the lab) to theoretical yield (maximum possible):

Percent Yield Formula:
% Yield = (Actual Yield Γ· Theoretical Yield) Γ— 100%

Why is percent yield less than 100%?

  • Incomplete reactions
  • Side reactions producing unwanted products
  • Product lost during purification/transfer
  • Measurement errors
Common Mistakes to Avoid
  • ❌ Forgetting to balance the equation first
  • ❌ Using grams instead of moles for comparison
  • ❌ Not dividing by stoichiometric coefficients
  • ❌ Assuming the reactant with less mass is limiting
  • βœ… Always convert to moles and use mole ratios!
Real-World Applications
  • Industrial Chemistry: Minimize waste by using excess of cheaper reactant
  • Pharmaceutical Manufacturing: Calculate exact amounts needed for drug synthesis
  • Environmental Chemistry: Predict pollutant formation in combustion
  • Food Chemistry: Optimize ingredient ratios in recipes
Results


Enter reactant amounts and click Calculate to see results

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